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  1. Describe all group homomorphisms from Z×Z into Z

    May 25, 2018 · I find a similar post, which is Describe all ring homomorphisms from Z×Z into Z. I also know the difference between group and ring. But in this case, from ZxZ into Z, I'm so …

  2. Convert from fixed axis $XYZ$ rotations to Euler $ZXZ$ rotations

    Convert from fixed axis $XYZ$ rotations to Euler $ZXZ$ rotations Ask Question Asked 13 years, 9 months ago Modified 11 years, 11 months ago

  3. $\mathbb {Z} \times \mathbb {Z} $ is a PID or not? [duplicate]

    we know Z is a PID but there exists no ring isomorphism between ZxZ and Z. So based on this observation can we conclude that ZxZ is not a PID ? I dont think we can because if A and B …

  4. What does Z —> Z x Z mean in this question? : r/learnmath - Reddit

    Feb 25, 2020 · ZxZ is the Cartesian product of Z. You'd have met this a long time ago as co-ordinates, (x,y) where both x and y are in Z. f is a function from Z to ZxZ, f (0) for example is …

  5. Does there exist a group isomorphism from Z to ZxZ?

    Apr 1, 2015 · Interesting way to think about it. So, in general, can you never have an isomorphism from a cyclic group to a non-cyclic group of the same order?

  6. Cardan angle (zxz, zxzxz) rotation - Mathematics Stack Exchange

    On the wikipedia page there is a listing of 12 matrices that can be used to represent a yaw-pitch-roll rotation series (YXZ) as a ZXZ rotation, or an XZX rotation, or an XZY rotation.. 1) Should t...

  7. Describe all ring homomorphisms - Mathematics Stack Exchange

    Jun 3, 2015 · Describe all ring homomorphisms of: a) $\\mathbb{Z}$ into $\\mathbb{Z}$ b) $\\mathbb{Z}$ into $\\mathbb{Z} \\times \\mathbb{Z}$ c) $\\mathbb{Z} \\times \\mathbb{Z ...

  8. su (2) vs ZXZ decomposition - Mathematics Stack Exchange

    Aug 31, 2023 · su (2) vs ZXZ decomposition Ask Question Asked 2 years, 4 months ago Modified 2 years, 4 months ago

  9. Proving a Function is OntoIs f: ZxZ->Z an onto function?

    Sep 14, 2008 · The function f: ZxZ->Z defined by f (m, n) = 2m - n is proven to be onto, as for every integer y, there exists at least one integer pair (m, n) such that f (m, n) = y. The proof …

  10. Presentation $\langle x,y,z\mid xyx^ {-1}y^ {-2},yzy^ {-1}z^ {-2},zxz ...

    Problem: Show that the group given by the presentation $$\\langle x,y,z \\mid xyx^{-1}y^{-2}\\, , \\, yzy^{-1}z^{-2}\\, , \\, zxz^{-1}x^{-2} \\rangle $$ is equivalent ...